$2^8+2^8=8^3$
How does coprime condition invalidate this solution?
2, 2, and 8 are not coprime since they share a common factor of 2. Beal’s conjecture only applies if A, B, and C (the bases) share no common factor greater than 1 i.e. are coprime
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2, 2, and 8 are not coprime since they share a common factor of 2. Beal’s conjecture only applies if A, B, and C (the bases) share no common factor greater than 1 i.e. are coprime