Can someone explain what a "discrete" function really means, in a philosophical sense, in plain English?
As a guess, does discrete mean there are only points with known values, and nothing in between? And if that's the case, is it possible to truly know what's in between the points somehow?
I mean, linear interpolation would be "fudging it" of course, simplifying a curve to a series of lines. Polynomial interpolation maybe?
Is there a way to 100% accurately represent what would go in between the dots?
Come to mention it, aren't all computed values "discrete"? I.e., when the graphing calculator, or desmos.com or whatever, draws out a graph, isn't it actually plotting a series of output values of an equation, only at small enough increments that you can't see the gaps?
So what I'm asking is, is there actually a deeper, fundamental difference between a discrete function like
y_0 = 10
y_(i+1) = C/2 + y_i
vs a "regular" function like
y = x
or is it just a matter of similar patterns being represented differently by the computer? Bc both functions can go on forever. And even though the first progresses in discrete "steps," the pattern that it represents must exist at a smaller scale, just maybe not "captured" by the "lens" of this equation? Idk.
A discrete set in a metric space or other topological space, such as the line or the plane or $3$-dimensional Euclidean space, is a space in which every points is (topologically) isolated, and that means each point in the set has an open neighborhood that contains no other points in the set.
For example, the set of integers $\{0,\pm1,\pm2,\pm3,\ldots\}$ is discrete because about every integer, say for example $5,$ you can find an open interval, say $(5-0.1,5+0.1),$ which contains no other integer.
And the set $\left\{ \tfrac 1 n : n=1,2,3,\ldots\right\}$ is discrete, but but if you add the limit point $0,$ getting $\left\{ \tfrac 1 n : n=1,2,3,\ldots\right\} \cup\{0\},$ that is not discrete because $0$ is a limit point rather than an isolated point. In other words, no matter how small an open interval you consider that contains $0,$ that interval also contains other members of the set.
A discrete probability distribution is one consisting entirely of point masses. Thus if a random variable (capital) $X$ has the property that $\sum_x \Pr(X=x)=1,$ where the sum is over all values (lower-case) $x$ that (capital) $X$ could be equal to.