What form is this equation $Z1 = r^2(\sin (\theta) + i\cos(\theta))$?

Question

Is it supposed to be triangular or what exactly?

$Z1 = \sin (\pi / 3) + i\cos(\pi / 3)$

It's a complex number btw. $r = 1$ and $\theta = \pi / 3$ btw.

Just asking. I didn't see an equation like that before. I knew how to convert it to the Rectangular. Just asking.

Answer 1

That's not an equation, that is, as you said, a complex number. There's nothing to solve.

Answer 2

You can think of $\sin (\pi / 3) + i\cos(\pi / 3)$ as already in rectangular form. The real part is $\sin(\pi/3) = \frac{\sqrt{3}}{2}$ and the imaginary part is $\cos(\pi/3) = \frac{1}{2}$.

Aside
$\sin (\pi / 3) + i\cos(\pi / 3)$ is not polar form with modulus $r=1$ and argument $\theta = \pi/3$. That would be $\cos (\pi / 3) + i\sin(\pi / 3)$.