In the Appendix to Chapter 8 of Spivak's Calculus, entitled "Uniform Continuity", there is the following theorem
If $f$ is continuous on $[a,b]$, then $f$ is uniformly continuous on $[a,b]$
The absence of the converse seems to imply that it isn't true. What is an example of a function that is uniformly continuous but not continuous on an interval $[a,b]$?
Not really. The absence of the converse sometimes means that it isn't true. Other times, it means that the converse is more broadly true.
In this case, the converse is more broadly true. In fact, if $I$ is a bounded interval, and $f: I\to\mathbb R$ is uniformly continuous, then $f$ is continuous on $I$. The converse is only true if $I$ is a closed interval.
In other words,