My brother brought something to my attention earlier this morning and I cannot find the answer with just a googling to end the argument, so I have come to you to ask and understand.
$(0! \ 0! \ 0!) = n$
He says that $n$ is $6$. I say that $n$ is $1$.
My reasoning: $0!=1$ so $1*1*1=1$
His reasoning: He won't explain it because he doesn't want to argue about it anymore, but he did mention something about absolute value, which didn't make sense because I saw no $||$ anywhere in the equation.
I don't care who's right. I just want to know what the right answer is and how this equation is solved.
UPDATE: So, since I spoke to him and showed him what all of you said, he said that the equation was actually $(0!+0!+0!)!=6$, which means that what was written on the piece of paper that he had given me was written in error.
If you mean "what is the factorial of (zero cubed)?", then$$\left(0^3\right)!=0!=1.$$
If you mean "what is (the factorial of zero) cubed?", then $$\left(0!\right)^3=1^3=1.$$
In either case, you're correct.
To see why $0!=1,$ see this.