If someone buy $260$ tickets such that to win with a ticket he needs to choose $6$ correct numbers from $42$ numbers.
What is his probability to win from one ticket?
If someone buy $260$ tickets such that to win with a ticket he needs to choose $6$ correct numbers from $42$ numbers.
What is his probability to win from one ticket?
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I'm assuming that the question "What is his probability to win from one ticket?" means "What is his probability to win from (at least, not exactly) one ticket?", otherwise it's not clear to me the reason of having 260 tickets and not only one.
In this case, the probability you look for is 1 minus the probability that there is no a winning ticket (among the 260 ones). Let $X_i$ be the Bernoulli random variable telling you whether or not you win with ticket $i$. Then, its success parameter is $p=1/{ 42 \choose 6 }$ and the $X_i$'s are assumed independent. So, you want to compute $$ 1-P(X_1=0 \cap\ldots \cap X_{260}=0) = 1 - \prod_{k=1}^{260} P(X_k=0) = 1-(1-p)^{260}. $$