The total resistance of two resistors connected in parallel is given by the formula: $$\frac{1}{R} = \frac{1}{R_{1}} + \frac{1}{R_{2}}$$
What is the maximum possible error (absolute) if we have $R_{1} = 6 \pm 0.1\Omega$ and $R_{2} = 8 \pm 0.3\Omega$
(Hint: first write the formula in explicit form $R = \dots$ and calculate the total differential of this expression).
I use hint and I got to this formula $$dR = \frac{R_{2}^2}{(R_{1}+R_{2})^2}dR_{1} + \frac{R_{1}^2}{(R_{1}+R_{2})^2}dR_{2}$$ I have a written solution and that is $0.088\Omega$ but I do not know what exactly I put into the given formula?