If $13!/2^x$ is an integer, which of the following represents all possible values of $x$?
a) $0 \le x \le 10$
b) $0 < x < 9$
c) $0 \le x < 10$
d) $1 \le x \le 10$
e) $1 < x < 10$
The book says d). But why can't it be a)? Since $13!/2^0$ is also an integer, right?
Yes you are right and the book is wrong.
13! has six factors of two, three factors of four, and one factor of eight, so $13!/2^{10}$ is an integer, and $13!/1=13!/2^0$ is an integer.