Help me find the common denominator please!
Thank you
Here it is :
$$\dfrac{5}{3x+2}-\dfrac{3}{3x-2}=\dfrac{7}{6x-4}+\dfrac{x+4}{18x^2-8}. 1$$
Help me find the common denominator please!
Thank you
Here it is :
$$\dfrac{5}{3x+2}-\dfrac{3}{3x-2}=\dfrac{7}{6x-4}+\dfrac{x+4}{18x^2-8}. 1$$
On
To find common denominators, factoring usually gives you the result. This equation is no exception.
$18x^2-8$ can be factored as $2(3x+2)(3x-2)$.
$6x-4$ can be factored as $2(3x-2)$. Multiplying $6x-4$ by $3x+2$ gives you $18x^2-8$.
$3x+2$ is not factorable. Multiplying it by $2(3x-2)$ gives you $18x^2-8$.
$3x-2$ is not factorable. Multiplying it by $2(3x+2)$ gives you $18x^2-8$.
Therefore $18x^2-8$ is the least common multiple.
Be sure that you need to check all factors in the denominator and then, determine the least common denominator that is divisible by all known denominators. That is...
Observe that $6x - 4 = 2(3x - 2)$ and $18x^2 - 8 = 2(9x^2 - 4) = 2(3x - 2)(3x + 2)$. Then, the least common denominator of that expression is $2(3x + 2)(3x - 2)$; $3x - 2$, $6x - 4$ and $18x^2 - 8$ have the common factor of $3x - 2$, whereas $18x^2 - 8$ and $3x + 2$ has the common factor of $3x + 2$.