What is the eigenvalue for characteristic polynomial $(1+\lambda^2)\lambda$?
Is it $0,i,-i$ or $0,i,i$?
2026-03-30 10:16:59.1774865819
What is the eigenvalue for characteristic polynomial $(1+\lambda^2)\lambda$?
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You can factorize your characteristic polynomial as $$p(\lambda)=\lambda(\lambda+i)(\lambda-i)$$ So, the eigenvalues (roots of the polynomial) are $0,i,-i$