I am doing the CAD for a Acute Golden Rhombohedron, and I want to form it by having 2 parallel Golden Rhombus, and offset one of them by the long axis (X), and the face to face axis(Z).
I am following the size of the Golden Rhombus here https://mathworld.wolfram.com/images/eps-svg/GoldenRhombus_1000.svg
What would be the length of those offsets?
Edit: Using the formula for the volume and area I have work out the height to be $\frac{a\sqrt{5(10+2\sqrt{5})}}{10}$ and I can find the X offset with Pythagoras' theorem. But I would appreciate it if someone can tell me how to work this out without "cheating"