What is the graph of$|x|+2|y|+3|z|\leq 1$?

Question

What is the graph of$|x|+2|y|+3|z|\leq 1$ ? And determine its geometrical figure. I know that the graph will be 3D. If I assume that $x \geq 0$,$y \geq 0$,$z \geq 0$. So let $x'^2 = x \geq 0$,$y'^2 = y \geq 0$,$y'^2 = z \geq 0$. Then above inequality can be written as $x+2y+3z\leq 1$ and $x'^2+2y'^2+3z'^2\leq 1 \implies \frac{x'^2}{1}+\frac{y'^2}{1\over2}+\frac{z'^2}{1\over3}\leq 1$ which is ellipsoid and its interior. Please help me.