what is the inverse of
$$G(x):=\exp(-\exp(-x))?$$
$$y=\exp(-\exp(-x))$$ $$\ln(y)=-\exp(-x)$$ $$-\ln(y)=\exp(-x)$$ $$\ln(-\ln(y))=-x$$ $$-\ln(-\ln(y))=x$$
So the inverse function is $$G^{-1}(x)=-\ln(-\ln(x))$$
Let $y=e^{-e^{-x}}$ then $\ln y=-e^{-x}\implies -\ln y= e^{-x}\implies \ln((-\ln y))=-x\implies x=-\ln((-\ln y))$
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$$y=\exp(-\exp(-x))$$ $$\ln(y)=-\exp(-x)$$ $$-\ln(y)=\exp(-x)$$ $$\ln(-\ln(y))=-x$$ $$-\ln(-\ln(y))=x$$
So the inverse function is $$G^{-1}(x)=-\ln(-\ln(x))$$