The perimeter of a square is 48 inches. What would be the length, in inches, of its diagonal?
2026-05-14 19:04:14.1778785454
What is the length of the diagonal of a square with perimeter $48$ inches?
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Since the perimeter of the square is 48 inches, each side is 12 inches. Using the Pythagorean theorem ($a^{2}$ + $b^{2}$ = $c^{2}$), we have $$12^{2}+12^{2} = diagonal^{2}$$ $$288 = diagonal ^{2}$$
Thus, the diagonal is about $16.97$ inches.