What is the probability of getting exactly one ace if i drew 4 cards at random from a standard deck of 52 playing cards?

Question

I used combinations and got (4C1*48C3)/52C4 which roughly comes out to be 0.256 which is ~26%. I'm not sure if this is correct or not.

Answer 1

Your answer is correct. There is another way to solve this though:

Probability of drawing the ace in the first draw: $P_1 = 4/52\times48/51\times47/50\times46/49$

Probability of drawing the ace in the second draw: $P_2 = 48/52\times4/51\times47/50\times46/49$

Probability of drawing the ace in the third draw: $P_3 = 48/52\times47/51\times4/50\times46/49$

Probability of drawing the ace in the fourth draw: $P_4 = 48/52\times47/51\times46/50\times4/49$

So, the probability of drawing exactly one ace $= P_1 + P_2 + P_3 + P_4 = 4 \times P_1=25.56\%$