Here' my reasoning:
The total possible combinations are $52\cdot52\cdot52$; the combinations starting with $h_1h_1$ are $52$, with $h_1h_2$ are $52$, ... with $h_{13}h_{13}$ are $52$, so there should be $52\cdot13\cdot13$ ways to have the first 2 cards as hearts. Then regarding the possibility $CHH$ I thought the situation was symmetric; taking from it the doublecount of the $HHH$ I concluded the probability is $\dfrac{2\cdot52\cdot13\cdot13-13\cdot13\cdot13}{52\cdot52\cdot52}=\dfrac7{64}$
But this is not among the given options, what is my mistake? How to fix it?
(I'm answering so that the question doesn't remain unanswered, once I can accept this)
The answer is correct, there was a typo in the question.