Suppose that you just received a shipment of six televisions and two are defective. If two televisions are randomly selected, compute the probability that both televisions work.
here is my work and steps to solve it I believe you should set up a fraction of the working televisions over the total televisions like this (4/6)*(3/5) E=(4/6) and F=(3/5) P(E and F) 6=total televisions 2=don't work 4=work
First pick one tv. Then pick another.Probability(both good) =Pr(first good)Pr(second tv good| given that first was good) =$\frac{4}{6} \times \frac {3}{5}=\frac{2}{5}$