I have a list of distances (doesn't matter what the distance is of for this question), the list goes like this:
Distance of 1 occurs 2.5% of the time
Distance of 2 occurs 2.5% of the time
Distance of 4 occurs 2.5% of the time
Distance of 5 occurs 2.5% of the time
Distance of 7 occurs 2.5% of the time
Distance of 8 occurs 2.5% of the time
Distance of 13 occurs 7.5% of the time
Distance of 14 occurs 5.0% of the time
Distance of 15 occurs 2.5% of the time
Distance of 16 occurs 2.5% of the time
Distance of 18 occurs 2.5% of the time
Distance of 20 occurs 2.5% of the time
Distance of 21 occurs 2.5% of the time
Distance of 22 occurs 2.5% of the time
Distance of 23 occurs 2.5% of the time
Distance of 25 occurs 5.0% of the time
Distance of 26 occurs 2.5% of the time
Distance of 27 occurs 2.5% of the time
Distance of 30 occurs 2.5% of the time
Distance of 35 occurs 5.0% of the time
Distance of 37 occurs 2.5% of the time
Distance of 38 occurs 2.5% of the time
Distance of 40 occurs 2.5% of the time
Distance of 49 occurs 2.5% of the time
Distance of 50 occurs 2.5% of the time
Distance of 55 occurs 2.5% of the time
Distance of 61 occurs 2.5% of the time
Distance of 62 occurs 2.5% of the time
Distance of 64 occurs 2.5% of the time
Distance of 74 occurs 2.5% of the time
Distance of 78 occurs 2.5% of the time
Distance of 86 occurs 2.5% of the time
Distance of 88 occurs 2.5% of the time
Distance of 89 occurs 2.5% of the time
Distance of 193 occurs 2.5% of the time
I want to know the probability in percentage of the "distance" reaching 13 OR above.
I'm guessing that it has an 85% chance, but I just want to make sure.
If all the percentages sum to 100% (I didn't check but I assume they do), then the answer is the sum of all percentages from the line
on.
This is simply because if two events $A,B$ are mutually exclusive, then $P(A\text{ or }B) = P(A)+P(B)$.