Can someone please help me in solving this problem.
if $\sqrt{x} + \sqrt{y} = 5+2\sqrt{6}$, then $x + y$ is equal to
(a) $2\sqrt{6}$
(b) $5-2\sqrt{6}$
(c) $5$
(d) $2\sqrt{6}$
Can someone please help me in solving this problem.
if $\sqrt{x} + \sqrt{y} = 5+2\sqrt{6}$, then $x + y$ is equal to
(a) $2\sqrt{6}$
(b) $5-2\sqrt{6}$
(c) $5$
(d) $2\sqrt{6}$
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If we trust in the strict equality then
$$\sqrt{x} + \sqrt{y} = 5 + 2\sqrt{6}$$
might mean
$$\sqrt{x} = 5 \to x = 25$$
$$\sqrt{y} = 2\sqrt{6}\to y = 24$$
Hence
$$x + y = 25 + 24 = 49 = \text{none of them}$$
Otherwise, just write the equation
$$\sqrt{x} + \sqrt{y} = 5 + 2\sqrt{6}$$
Square it and try to get a solution, which be, by the way, not unique since one parameter is free (either $x$ or $y$).