What is the Z-Transform $u_n =\cos(n+1)\theta$?

261 Views Asked by At

I have tried using the putting it into $\cos(n\theta)$ = $\frac{z (z-cos\theta)}{z^2 - 2zcos\theta+1}$ formula, but my answer is wrong.

$u_n = \cos(n+1)\theta.$