I have tried using the putting it into $\cos(n\theta)$ = $\frac{z (z-cos\theta)}{z^2 - 2zcos\theta+1}$ formula, but my answer is wrong.
$u_n = \cos(n+1)\theta.$
I have tried using the putting it into $\cos(n\theta)$ = $\frac{z (z-cos\theta)}{z^2 - 2zcos\theta+1}$ formula, but my answer is wrong.
$u_n = \cos(n+1)\theta.$
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