I'm new here and using this for my coding project, so please give answers in a simple form if possible!
I have a train. Let's say its moving at 50kph ($s$). The next speed board/marker is for 80kph ($v$) and it is 100 meters ($d$) away. My train accelerates/decelerates at a constant speed of 0.5m/s ($a$). If it starts accelerating now, what's the maximum speed ($m$) it will reach at the speed board?
Any help is greatly appreciated :) Thanks!
Use the equation $v^{2}=u^{2}+2as$ where $v$ is the final (maximum in this case) velocity, $u$ is the initial velocity, and $a$ is the accelaration. This gives $$v^{2}=13.8^{2}+2(0.5)(100)=292.89$$ (after converting km/h to m/s) and therefore $$v = (292.89)^{1/2} = 17.11~\text{m/s} = 61.6~\text{km/h}$$