What's the probability density of r.v. $Y = X + f(X)$ if the density of r.v. X is p(X)?

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Is there a way to derive an expression for the density of the transformation of a continuous random variable $X$ (with prob. density $p(X)$ supported on $\mathbb{R}^d$) as follows?

$$Y = X + f(X)$$

What properties must $f$ satisfy for this to be possible?

I know that we can derive an expression for the density of a transformation $Z = f(X)$ when $f$ is a smooth, invertible function.

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We have $$ \mathbb P(Y\le t) = \mathbb P(X + f(X)\le t) $$ so if we have a formula for $f$, gathering the conditions for which $X + f(X)\le t$, we can retrieve the density probability function $P_{X+f(X)}$ by differentiating $F_Y(t) = \mathbb P(Y\le t)$.

Example: $f=\rm Id$ gives $F_Y(t) = F_X(\frac t 2 )$.