What was the initial velocity in the y direction $v_x = 3.6 \text{ m/s} \times \cos 18°$?

152 Views Asked by At

A ball is thrown, it's path is oblique; it's velocity is depicted by the $x$-axis formula $v_x = 3.6 \text{ m/s} \times \cos 18°$. What was the initial velocity in the $y$ direction?

I have no idea how to calculate the answer?

1

There are 1 best solutions below

3
On

I do not understand what you mean with "oblique". In any case, if your initial velocity vector has length $v$, then you are asking for the length of the component parallel to the y-axis, i.e. $v_y$, with $v_x$ given. As $v_x=v \cos 18°$ and $v_y=v \sin 18°$, then using $v=3.6\text{ m/s}$ you find $v_y=3.6*\sin 18°\text{ m/s}$.