When is $R^{op}\cong R$?

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Suppose $R$ is a noncommutative ring. When could I reasonably expect $R^{op}\cong R$?

For instance I know group rings have a natural involution, i.e. if $SG$ is the group ring in question then $r\cdot g=g^{-1}\cdot r$. Does this imply $S[G]^{op}\cong S[G]$? If so, does this apply to any ring with a natural involution?

Finally, does $R^{op}\cong R$ imply all left ideals are right ideals (and vice versa)?