When maximum operator produces smooth functions?

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Given $f\in C^{\infty}(\Omega)$, with $\Omega \subseteq [-1,1]^2$, define

$$M[f](x):=\max_{y:(x,y)\in \Omega} f(x,y).$$

It is easy to show that this function may not be smooth: if $f(x,y)=xy$ and $\Omega=[-1,1]^2$ we have

$$M[f](x)=|x|\notin C^{1}(\Omega).$$

Eevn for $\Omega = B_1(0)$, the unit ball, which has smooth boundary, we get

$$M[f](x)=|x|\sqrt{1-x^2}\notin C^{1}(\Omega).$$

which is not smooth either. Note that that by Danskin's theorem we have a sufficient condition for $M[f]\in C^1$, but I know no results for higher order of differentiability. Is there some assumption on $f,\Omega$ under which $M[f]$ is more than one time differentiable?