Where is the curvature minimal?
Now I have found where the curvature is maximum. How ever I don't know how to solve for the minimum.
$$\vec{r}(t)=2\cos(t)\vec{i}+3\sin(t)\vec{j}$$
I used the equation to solve for kappa.
$$\kappa (t)=|\vec{r'(t)} \times \vec{r''}(t) |/|\vec{r'}(t)|^{3}$$
Can anyone give me some input? Thanks