If we know that $(f\circ f)(x)=4x+3$, with $f(0)=4$, what is $f(3)=?$
I have found that $f(f(x))= 16x+15$, but I don't know where to go from there.
If we know that $(f\circ f)(x)=4x+3$, with $f(0)=4$, what is $f(3)=?$
I have found that $f(f(x))= 16x+15$, but I don't know where to go from there.
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Notice that $f(0)=4$ and $f(f(0))=3$, so $f(4)=3$ which implies $f(3)=f(f(4))=19$.