$x$ and $y$ are non-negative integers.
Then which one is greater or both are equal: $$ \sqrt{x} + \sqrt{y} \text{ or } \sqrt{x+y}? $$
$x$ and $y$ are non-negative integers.
Then which one is greater or both are equal: $$ \sqrt{x} + \sqrt{y} \text{ or } \sqrt{x+y}? $$
Copyright © 2021 JogjaFile Inc.
$\sqrt x+\sqrt y$ will be $\ge\sqrt{x+y}$
iff $(\sqrt x+\sqrt y)^2\ge (\sqrt{x+y})^2$
iff $x+y+2\sqrt{xy}\ge x+y$
if $\sqrt{xy}\ge 0$ which is true
The equality occurs if at least one of $x,y$ is $0$