How to proof or transform this inequality to be true?
$$(2n+2)! ≥ (n+2)! (n+2)^n$$
2026-03-29 11:43:32.1774784612
Why $(2n+2)! ≥ (n+2)! (n+2)^n$ is true?
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We have that
$$(2n+2)!=\overbrace{(2n+2)(2n+1)\dots(n+3)}^{\text{n terms}}(n+2)!$$