$y^2=4ax$
$y= \pm 2 \sqrt {ax} $
Now, we have two cases. And after differentiating both we get two different slopes which is not possible.
$\frac {dy}{dx} = \pm \frac {2a}{y}$
What am I doing wrong?
$y^2=4ax$
$y= \pm 2 \sqrt {ax} $
Now, we have two cases. And after differentiating both we get two different slopes which is not possible.
$\frac {dy}{dx} = \pm \frac {2a}{y}$
What am I doing wrong?
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Be careful $$y= \pm 2 \sqrt {ax}\implies \frac {dy}{dx} = \pm \frac {2a}{2 \sqrt {ax}} =\pm \frac {2a}{\pm y} = \frac {2a}{ y} $$
Your mistake was in substitution of $ 2 \sqrt {ax}$ for $y$