Peter Taylor pointed out at MathEduc that some BD$1 coins from 1997 are Reuleaux triangles:
(Image from de.ucoin.net.)
Does anyone know why they were shaped this way? Was there some pragmatic reason connected to its constant-width property? Or was it just a design/aesthetic decision?
The area of the Reuleaux triangle of unit width is $\frac{\pi - \sqrt{3}}{2} \approx 0.705$, which is approximately $90\%$ of the area of the disk of unit diameter. Therefore, if one needs to mint (convex) coins of a given constant width and thickness, using Reuleaux triangles allows one to use approximately $10\%$ less metal.
$\dagger$ Evans M. Harrell, A direct proof of a theorem of Blaschke and Lebesgue, September 2000.