Why arsin function has range $[-\pi/2,\pi/2]$

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While studying in P.75 of inverse trigonometric functions it tells we have to restrict our domain before finding the inverse.But I can't get why we choose $[-\pi/2,\pi/2]$?Why can't we choose $[\pi/2,3\pi/2]$ where the function arcsin is invertible on this interval?

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You totally can. You can choose any interval where it's invertable. It's just "natural" to choose $[-\pi/2,\pi/2]$ as most "real" angles are around there.