I'm currently learning how to differentiate, but as most entirely new things are rather abstract, I cannot really get a hold of the reason why I'm differentiating.
For example, we have a function, $y=x^3$. The derivative of $x^3$ is written as $y'=3x^2$. The differential of $x^3$ could be written as $d(x^3)=3x^2\,dx.$
Okay, I think. What then, I wonder? This is not really telling me anything. Beautiful math, though.
(The answers to what is the use of derivatives do not give me very much mathematical intuition behind why we differentiate.)

It is telling you something very important.
The derivative of a function $y = f(x)$ at $x$ is defined as $$f'(x) = \lim_{h\to 0}\dfrac{f(x + h) - f(x)}{(x+h) - x}$$ Now, try to analyse the expression. What do we mean by $f(x + h) - f(x)$? That is nothing but the change in $y$. And what do we mean by $(x + h) - x$ ? It is the corresponding change in $x$ which evaluates to $h$.
In the image, $f(x+h)-f(x) = AC$ and $h = BC$. $$\dfrac{f(x + h) - f(x)}{h} = \dfrac{AC}{BC}$$ And $\dfrac{AC}{BC}$ is the slope of the secant $AB$. Now, if $h$ gets closer and closer to $0$, the point $A$ will get closer and closer to point $B$, given the function is differentiable (which also implies it is continuous). In the limit as $h$ approaches $0$, $A$ would come infinitesimally close to $B$.
Therefore, the expression $$\lim_{h\to 0}\dfrac{f(x + h) - f(x)}{h}$$ would give us the slope of the tangent line to the graph at point $B$. This is what the derivative tells us. It gives the slope of a function at a given point.
Because derivative gives you the rate of change of $y$ with respect to $x$. And this information is used widely in physics. For example if you are given the displacement an object as a function of time and you want to know its velocity at a particular point of time, you need to find the derivative of the displacement function with respect to time to get velocity as a function of time (because velocity is the rate of change of displacement with respect to time).