Why does $\dfrac{2}{\sqrt{-4x^2-4x}}$ simplify into $\dfrac{1}{\sqrt{-x^2-x}}$?
What's going on here? How is it being simplified?
2026-03-29 06:30:31.1774765831
Why does $\dfrac{2}{\sqrt{-4x^2-4x}}$ simplify into $\dfrac{1}{\sqrt{-x^2-x}}$?
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$$\dfrac{2}{\sqrt{-4x^2-4x}}=\dfrac{2}{\sqrt{4(-x^2-x)}}=\dfrac{2}{\sqrt{4}\sqrt{(-x^2-x)}}\\ =\dfrac{2}{2\sqrt{(-x^2-x)}}=\dfrac{1}{\sqrt{(-x^2-x)}}$$