Why does $\frac{1}{4}x^{-3/4} = \frac{1}{4x^{3/4}} = \frac{1}{4\sqrt[4]{x^3}}$?

967 Views Asked by At

This is taken from Khan Academy, I don't understand how these equate:

$$\frac{1}{4}x^{-3/4} = \frac{1}{4x^{3/4}} = \frac{1}{4\sqrt[4]{x^3}}$$

How come the minus was remove from the original exponent?

1

There are 1 best solutions below

1
On

These are properties of exponentiation. In particular,

$$a^{-b} = \frac{1}{a^b}$$

combined with

$$a^{\frac{m}{n}} = \sqrt[\leftroot{-2}\uproot{2}n]{a^m}.$$

In your case,

$$\frac{1}{4}x^\frac{-3}{4} = \frac{1}{4x^\frac{3}{4}} = \frac{1}{4\sqrt[\leftroot{-2}\uproot{2}4]{x^3}}.$$