Why does this improper integral converge

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I can't understand a part of a proof. Here is the strange part isolated.

Let $1<q<2$. Then

$(\int_{|z-\tau|\leq R}\frac{d\tau}{|z-\tau|^q})^q = (\frac{2\pi R^{2-q}}{2-q})^q$

The integral is over complex numbers. It seems to me that the integral diverges, but I suspect this has something to do with improper integrals. Unfortunately, I am not very familiar with them in this setting. Could someone help me with this?