I had this question in an exam:
In the triangle below, $AB = 12cm$, $BC = 19cm$ and $AC = 14cm$. Calculate the area of the triangle.
The answer to this question finds the angle $A$ using the cosine rule and then uses this formula to find the area:
$$ \frac { 1 }{ 2 } ab \sin { A } $$
Why can't I just use Heron's formula, where the area of $\triangle ABC$ with perimeter $S$ is:
$$ \sqrt { s(s - a) (s - b) (s - c) } $$
This is a GCSE question.

Bit late on this I know.
Heron's formula is fun but often painful and long; most of the time in GCSE it would be much more work. It is also off-syllabus as the GCSE course tries to teach you trigonometry - so there is no point in teaching you shortcuts for trigonometry right now as the cosine rule etc. will lead on to more important and difficult trigonometry in A Level maths, for example.