Why / How / What is the intermediate step to perform this step?

Question

Here is the expression.

$$\frac { { 10 }^{ n+1 }n! }{ { 10 }^{ n }(n+1)! } =\frac { 10n!\quad { 10 }^{ n } }{ (n+1)n!\quad { 10 }^{ n } } $$

Can someone help me see the intermediate steps expanded?

Answer 1

$$\frac { { 10 }^{ n+1 }n! }{ { 10 }^{ n }(n+1)! } =\frac { \overset { n+1 }{ \overbrace { 10\cdot 10\cdot ...\cdot 10 } \quad } }{ \overset { n }{ \overbrace { 10\cdot 10\cdot ...\cdot 10 } \quad } } \cdot \frac { 1\cdot 2\cdot 3...\cdot n }{ 1\cdot 2\cdot 3...\cdot n\cdot \left( n+1 \right) } =\frac { 10 }{ n+1 } $$