Assume m, b are positive integers.
$(-1)^{3m/2}$ can be written as $\sqrt{(-1)^{3m}}$. If m is even, then $(-1)^{3m}=1$, otherwise $(-1)^{3m}=-1$. Now $\sqrt{1}=1$ and $\sqrt{-1}=i$.
But why is then $(-1)^{3m/2}\cdot b^{3m/2} = (-b)^{3m/2}$?
2026-03-28 11:22:07.1774696927
why is $(-1)^{3m/2} \cdot b^{3m/2} = (-b)^{3m/2}$?
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