Why is $M$ bounded in $\mathscr L^2$ iff $E[\lim A_n] < \infty$?

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Probability with Martingales:


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About $(c)$

My understanding is that $(c)$ is equivalent to:

$$\sup E[A_n] < \infty \iff E[\lim A_n] < \infty$$

Why is that so?

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$$E[\lim A_n] = \lim E[A_n]\ \text{by MCT}$$

$$= \sup E[A_n] \ \because \ P(A_n \le A_{n+1}) = 1 \ \forall \ n \ \because \ P(A_n \le A_{n+1} \ \forall \ n) = 1$$