I have seen the following simplification:
$$\left|\frac{1}{(-1-\frac{1}{n})^4 - 1}\right| = \frac{1}{\left|-1-\frac{1}{n}\right|^4 - 1}$$
I really don't have a clue why this is possible...
I am sorry but I can't give any ideas because I don't have any.
Thank you for advice.
FunkyPeanut
Note that $x \geq 0$ if and only if $|x|=x$. So we have $\frac{1}{(-1-\frac{1}{n})^4 - 1}\geq 0$.
Inequlity $(-1-\frac{1}{n})^4 - 1\geq 0$ implies that $1+\frac{1}{n}\geq 1$. Hence for every natural number $n$, we have $|\frac{1}{(-1-\frac{1}{n})^4 - 1}| = \frac{1}{|-1-\frac{1}{n}|^4 - 1}$.