¿Why is the ordered square $[0,1]^{2}$ first countable in the dictionary order? I suppose for any point in $[0,1]^{2}$ I must find a countable basis, but I do not know yet what it should be or how to argue it.
2026-03-26 01:00:06.1774486806
Why is the ordered square $[0,1]^{2}$ first countable in the dictionary order?
47 Views Asked by Bumbble Comm https://math.techqa.club/user/bumbble-comm/detail AtRelated Questions in GENERAL-TOPOLOGY
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