Why is Torus a Kahler manifold?

Question

I've run into the following issue. I want to understand why a torus $T = \mathbb C^n / \Lambda$ where $\Lambda$ is a lattice, is a Kähler manifold?

Now, Wikipedia seems to suggest that it is because it inherits a flat metric coming from $\mathbb C^n$.

For me, to show Torus is a Kähler manifold would require to find a real $(1,1)$ form which is closed and a bunch of compatibility conditions.

1. How does flat metric imply any of this?

Elsewhere on Wikipedia itself they say a manifold is Kahler iff it is a $2n$ dim Riemannian manifold whose holonomy group is contained inside $U(n)$.

2. Does a flat connection have holonomy group inside $U(n)$? Why?

Any help will be highly appreciated.