Why the arccos of adjacent leg is not equal to arcsin to the oposit leg for the right triangle

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Silly question. I have a right triangle with adjacent leg $A = 81.67$ and an opposite leg $B = -1225.53$. So hypotenuse $C$ will be $\sqrt{(A^2 + B^2)} = 1228.25$.

$\arccos(A / C) = 1.50$ and $\arcsin(B / C) = 3.07$. Why are they not the same, what is the reason of difference? ( I have used python for calculations)

P.S. Negative size means that leg goes from origin to the negative X direction

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You did your computation wrong; the arcsin of $1225.53/1228.25$ is approximately $1.504$ radians.

The arcsin will never produce a value outside the range $-\pi/2 \le u \le \pi/2$, which is approximately $-1.57 \le u \le 1.57$.

(The original question had a negative-sign before the $1225.53$; in that case, the arcsin is $-1.504$ radians, again, not the same as $3.07$.)