Why the standard deviation of discrete random variable is not divided by n?

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The standard deviation formula actually makes sense to me.

$\sqrt(\frac1N\sum(x-u)^2)$

However, I do not understand why in the standard deviation of a discrete random variable formula

$\sqrt( \sum(x-u)^2p)$

the $\frac1N$ does not appear. Why it does not? What could be a graphical interpretation to understand the formula?

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If the discrete random variable is uniform over $N$ values, then the probability $p$ associated with each value $x$ that it takes is $1/N$, and you recover the standard deviation formula that makes sense to you.

More generally, random variables will not be uniform, so you replace $1/N$ with different probabilities $p$ associated with each $x$. This is the second expression in your post.