I was wondering if proving
$$p^2\cdot b-1=2^{2^n}$$
has no solutions in $\mathbb{N}$ for $p$ a prime, it would prove square freeness of fermat numbers?
I was wondering if proving
$$p^2\cdot b-1=2^{2^n}$$
has no solutions in $\mathbb{N}$ for $p$ a prime, it would prove square freeness of fermat numbers?
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