I have the following:
$$-11(0.1x-0.2)(0.3x-0.4)$$
I know that the answer is
$$−0.33x^2+1.1x−0.88 $$
But what steps do i need to take to write it in standard form? I don't fully grasp the steps, so if anybody would like explain them to me I'd feel blessed.
$-11(0.1x-0.2)(0.3x-0.4)$
Use the distributive property.
Where do you want to distribute first?
How about breaking up $(0.1x) + (-0.2)$
The other factors multiply by each of these terms.
$-11(0.1x)(0.3x-0.4)+(-11)(-0.2)(0.3x-0.4)$
Then we can multiply the $(-11)$ and $(-0.1x)$ factors and the $(-11)$ and $(-0.2)$ factors.
$(-1.1x)(0.3x-0.4)+(0.22)(0.3x-0.4)$
Keep distributing.
$(-1.1x)(0.3x)+ (-1.1x)(-0.4)+(0.22)(0.3x) + (0.22)(-0.4)$
Multiply
$-3.3x^2 + 0.44x +0.66x - 0.88$
Combine the $x$ terms.
$-3.3x^2 + 1.1x - 0.88\\ $