$x=3 \cos^3(t),\, y=3 \sin^3(t)$, rearrange for $t$, how to handle ($\cos^3$)

Question

I know arccos is the opposite of cos, in the way multiplication is the opposite of division,

$$ x=3 \cos^3(t),\, y=3 \sin^3(t) $$

but I am unsure how to rearrange the equation in terms of $t$, as I do not know how to handle $\cos^3$.

Answer 1

$$\begin{array}{rcl} 3\cos^3(t) &=& x\\ \cos^3(t) &=& \dfrac x3\\ \cos(t) &=& \sqrt[3]{\dfrac x3}\\ t &=& \arccos\sqrt[3]{\dfrac x3}\\ \end{array}$$