A function that is in $L^1(\mathbb{R})$ but not $L^{\infty}(I)$ for any open interval $I$?

36 Views Asked by At

A function that is in $L^1(\mathbb{R})$ but not $L^{\infty}(I)$ for any open interval $I$? This is an exercise from an old measure theory book I'm working through... I've been working trying to build stuff with intensely oscillating functions and log's and what not but can't come up with anything... Example appreciated!!

1

There are 1 best solutions below

2
On BEST ANSWER

Let $f(x) = x^{-1/2}\chi_{(0,1)}.$ Note $f$ is in $L^1$ but not $L^\infty.$ Now consider

$$g(x) = \sum_{n=1}^{\infty}\frac{f(x-r_n)}{2^n},$$

where $r_1,r_2,\dots$ are the rationals.