Given a circle on an Euclidean plane and a point $A$ outside the circle, find a line through $A$, tangent to the circle.
You're allowed to use a straight edge only.
2026-03-25 06:04:50.1774418690
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A tangent to a circle with a straight edge
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Generally speaking, Mohr-Mascheroni theorem asserts that whatever constructible by compass and straightedge can also be constructed by straightedge only. Of course, if you want to construct a circle, you surely need to satisfy with constructing 3 distinct points on it.
Draw two lines through $A$, crossing the circle. For the next step to be possible, the lines need be in different distances from (unknown...) center of the circle.
Name the intersections of one line and a circle $B$ and $C$, for the other line: $D$ and $E$:
Find a point $F$ at the intersection of lines $BD$ and $CE$, and $G$ at the intersection of $BE$ and $CD$:
Now find $H$ and $J$ as intersections of the line $FG$ with the circle:
Voilà: lines $AH$ and $AJ$ are tangent to the circle.